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Class 7 & 8 Guide LCM Word Problems for Class 7/8 — Complete Guide

LCM word problems are among the most essential application-based questions in Class 7 and Class 8 mathematics. They evaluate your ability to apply the Least Common Multiple to real-world scenarios such as bells ringing together, transport departures, gear teeth realignment, circular track laps, and tile dimensions. This guide provides 13 fully solved problems with diagrams and step-by-step solutions.

Introduction to LCM Word Problems

An LCM word problem is an applied mathematical scenario where you determine the smallest time period, distance, or quantity at which multiple repeating cycles synchronize.

Why Are LCM Word Problems Critical in Class 7 & 8?

Common Real-Life Problem Scenarios

Real-Life Scenario What Is Asked? How LCM Solves It
Bells ringing at fixed intervals When will all bells chime together next? LCM of interval periods
Buses departing depot routes When will all route buses depart at the same minute? LCM of route departure minutes
Interlocking gear wheels After how many teeth/rotations do marks realign? LCM of teeth counts
Athletes running around an oval track When will all runners meet at the start line? LCM of lap completion times
Division with a common remainder Smallest number leaving remainder r LCM of divisors + remainder r

How to Identify LCM Word Problems

Recognizing the problem type immediately saves precious exam time. Look for these core clues:

✓

LCM Clues (Synchronization)

"Together", "at the same time", "minimum", "least", "smallest", "repeat", "coincide", "realign", "meet again". The answer is larger than or equal to the individual inputs.

✗

HCF Clues (Division / Partition)

"Maximum", "greatest", "largest", "longest tape", "divide equally", "equal containers". The answer is smaller than or equal to the individual inputs.

Golden Rule: If multiple events are repeating into the future and you need their next common meeting point, always find the LCM.

4-Step Solution Method for Class 7/8

Follow this structured 4-step framework in your exams for full marks:

1

Extract Data & Check Units

List the numbers given. Ensure all intervals share identical units (e.g., convert minutes to seconds if needed).

2

Compute LCM

Find the LCM using prime factorization or the common division ladder method.

3

Convert Units

Convert the resulting LCM into the units requested by the question (e.g., seconds into minutes & seconds).

4

State Time / Quantity

Add the interval to the starting clock time (if given) and state the final answer with units.

1. Bell & Alarm Problems

Bells ringing at periodic intervals represent the quintessential LCM word problem in school curricula.

Diagram 1: Three Bells Timeline Synchronization (6, 8, and 12 Minutes)

Timeline tracks for three church bells tolling at intervals of 6, 8, and 12 minutes starting at 8:00 AM. Notice how Bell 1 rings 4 times, Bell 2 rings 3 times, and Bell 3 rings 2 times before they all toll together at 24 minutes (8:24 AM).

Bell 1 (Every 6 min): 0m 6m 12m 18m 24m Bell 2 (Every 8 min): 8m 16m 24m Bell 3 (Every 12 min): 12m 24m LCM = 24 min (8:24 AM)

Problem 1: Three Bells Tolling at Intervals

Question: Three bells ring at intervals of 6, 8, and 12 minutes respectively. If they toll together at 8:00 AM, at what time will they toll together next?

Step 1: Identify the numbers: 6, 8, and 12 minutes.
Step 2: Find LCM(6, 8, 12)
6 = 2 × 3
8 = 23
12 = 22 × 3
LCM = 23 × 3 = 8 × 3 = 24 minutes
Step 3: Add to start time
8:00 AM + 24 minutes = 8:24 AM
Answer: 8:24 AM

Problem 2: Traffic Lights at Three Crossings

Question: Traffic lights at three road junctions change after every 48, 72, and 108 seconds respectively. If they change simultaneously at 7:00:00 AM, at what time will they next change together?

Step 1: Intervals are 48 s, 72 s, and 108 s.
Step 2: Find LCM(48, 72, 108)
48 = 24 × 3
72 = 23 × 32
108 = 22 × 33
LCM = 24 × 33 = 16 × 27 = 432 seconds
Step 3: Convert to minutes and seconds
432 ÷ 60 = 7 minutes and 12 seconds.
Step 4: Next simultaneous time
7:00:00 AM + 7 min 12 sec = 7:07:12 AM
Answer: 7:07:12 AM

Problem 3: Two Alarm Clocks

Question: Two alarm clocks chime at intervals of 50 minutes and 60 minutes. If both chime together at 12:00 noon, when will they next chime together?

50 = 2 × 52
60 = 22 × 3 × 5
LCM = 22 × 3 × 52 = 4 × 3 × 25 = 300 minutes
300 minutes = 300 ÷ 60 = 5 hours
12:00 noon + 5 hours = 5:00 PM
Answer: 5:00 PM

2. Gear & Wheel Realignment Problems

Gears and wheels have integer counts of teeth or circumferences. The LCM determines when marked points return to their exact meshing alignment.

Diagram 2: Interlocking Gear Teeth Realignment (12 Teeth & 18 Teeth)

Gear A has 12 teeth and Gear B has 18 teeth. Marked teeth start meshed at 0. After Gear A completes 3 full turns (36 teeth) and Gear B completes 2 full turns (36 teeth), their marked teeth meet again at LCM(12, 18) = 36.

Gear A 12 Teeth Gear B 18 Teeth Meshing Point Gear Cycle Math: • 12 = 2² × 3 • 18 = 2 × 3² LCM = 2² × 3² = 36 teeth Gear A: 36 ÷ 12 = 3 rotations Gear B: 36 ÷ 18 = 2 rotations

Problem 4: Revolutions of Meshing Gears

Question: Two gears have 12 teeth and 18 teeth respectively. If they start meshing at a marked tooth, after how many rotations of the smaller gear will the marked teeth mesh together again?

LCM(12, 18) = 36 teeth.
Rotations of smaller gear = LCM ÷ teeth in smaller gear = 36 ÷ 12 = 3 rotations.
(Rotations of larger gear = 36 ÷ 18 = 2 rotations).
Answer: 3 rotations of the smaller gear

Problem 5: Wheels of Unequal Circumference

Question: Two bicycle wheels have circumferences of 24 cm and 36 cm respectively. What is the minimum distance the bicycle must travel so that both wheels complete an exact whole number of revolutions?

Required distance = LCM(24, 36).
24 = 23 × 3; 36 = 22 × 32
LCM = 23 × 32 = 8 × 9 = 72 cm
Answer: 72 cm

3. Athletes & Circular Track Problems

When athletes run on a closed track at constant speeds, their arrival at the starting line repeats in cycles of their individual lap times.

Diagram 3: Circular Track Lap Meeting Point (2, 3, and 4 Minutes)

Three runners start together at the start line. Runner A takes 2 min per lap, Runner B takes 3 min, and Runner C takes 4 min. All three coincide at the start line together after LCM(2, 3, 4) = 12 minutes.

START LINE Meeting At Starting Line: ● Runner A: 2 min / lap (Prime: 2¹) ● Runner B: 3 min / lap (Prime: 3¹) ● Runner C: 4 min / lap (Prime: 2²) LCM(2, 3, 4) = 2² × 3 = 12 min ✓ Laps completed: A=6 laps, B=4 laps, C=3 laps First meet at start point after exactly 12 min

Problem 6: Three Athletes Around a Circular Track

Question: Three athletes run around a circular track completing one lap in 2, 3, and 4 minutes respectively. If they start together from the starting point at 6:00 AM, after how many minutes will they all meet at the starting point again?

2 = 2¹
3 = 3¹
4 = 2²
LCM = 2² × 3 = 12 minutes
They meet again at 6:00 AM + 12 min = 6:12 AM
Answer: 12 minutes (at 6:12 AM)

4. Bus & Transit Depot Problems

Fleet dispatchers schedule public buses and trains in repeating headways.

Problem 7: Three Buses Leaving a Terminal

Question: Three inter-city buses leave a depot at intervals of 15 minutes, 20 minutes, and 30 minutes respectively. If they all depart together at 6:00 AM, at what time will they next depart simultaneously?

15 = 3 × 5
20 = 22 × 5
30 = 2 × 3 × 5
LCM = 22 × 3 × 5 = 4 × 3 × 5 = 60 minutes = 1 hour
6:00 AM + 1 hour = 7:00 AM
Answer: 7:00 AM

Problem 8: Regional Trains at a Junction

Question: Two express trains leave a railway junction at intervals of 40 minutes and 60 minutes. If both depart together at 9:00 AM, at what time will they next depart together?

40 = 23 × 5
60 = 22 × 3 × 5
LCM = 23 × 3 × 5 = 8 × 3 × 5 = 120 minutes = 2 hours
9:00 AM + 2 hours = 11:00 AM
Answer: 11:00 AM

5. Tile & Floor Dimension Problems

Understanding the distinction between tiling problems that require HCF versus LCM is a classic exam distinction.

Problem 9: Largest Square Tile to Cover a Floor (HCF Contrast)

Question: Find the size of the largest square tile that can pave a rectangular courtyard of length 180 cm and width 120 cm without cutting any tiles.

Tile size must divide both 180 and 120 evenly → Find HCF(180, 120).
180 = 22 × 32 × 5
120 = 23 × 3 × 5
HCF = 22 × 3 × 5 = 4 × 3 × 5 = 60 cm
Number of tiles = (180 ÷ 60) × (120 ÷ 60) = 3 × 2 = 6 tiles
Answer: 60 cm (requires 6 tiles)

Problem 10: Minimum Square Formed by Small Rectangular Tiles (LCM)

Question: What is the side length of the smallest square floor that can be completely paved using rectangular tiles of size 15 cm by 20 cm?

The square's side must be a common multiple of 15 and 20 → Find LCM(15, 20).
15 = 3 × 5
20 = 22 × 5
LCM = 22 × 3 × 5 = 4 × 3 × 5 = 60 cm
Number of tiles needed = (60 × 60) ÷ (15 × 20) = 3600 ÷ 300 = 12 tiles
Answer: 60 cm

6. Remainder & Equal Packaging Problems

Advanced competition problems often combine LCM with a fixed remainder.

Problem 11: Smallest Number with a Fixed Remainder

Question: Determine the smallest number which when divided by 12, 15, and 18 leaves a remainder of 5 in each case.

Step 1: Find LCM(12, 15, 18)
12 = 22 × 3; 15 = 3 × 5; 18 = 2 × 32
LCM = 22 × 32 × 5 = 4 × 9 × 5 = 180
Step 2: Add the common remainder: 180 + 5 = 185
Verification: 185 ÷ 12 = 15 (rem 5); 185 ÷ 15 = 12 (rem 5); 185 ÷ 18 = 10 (rem 5) ✓
Answer: 185

Problem 12: Equalizing Inventory Packages

Question: A shopkeeper sells sweets in packets of 15, 20, and 25 pieces. If a school wishes to buy equal counts of all three sweet varieties without opening any packet, what is the minimum count of each sweet type they must purchase?

Find LCM(15, 20, 25):
15 = 3 × 5; 20 = 22 × 5; 25 = 52
LCM = 22 × 3 × 52 = 4 × 3 × 25 = 300 sweets
Packets to purchase: 300 ÷ 15 = 20 packets, 300 ÷ 20 = 15 packets, 300 ÷ 25 = 12 packets.
Answer: 300 sweets of each type

Common Student Mistakes in Exams

Avoid these 5 common exam traps when tackling LCM word problems:

❌ Mistake Why It Is Incorrect ✅ Correct Procedure
Confusing LCM with HCF LCM is for synchronization (larger); HCF is for partition (smaller) If events repeat into future → LCM; if cutting or grouping → HCF
Forgetting to convert units Intervals in seconds added directly to minutes without division by 60 Convert seconds to minutes (e.g. 432 s = 7 min 12 s) before adding
Multiplying numbers instead of LCM For 6 and 8, using 6 × 8 = 48 rather than LCM = 24 Use prime factors: 23 × 3 = 24
Subtracting the remainder instead of adding Subtracting remainder 5 gives 175, which leaves no remainder when divided Required number = LCM + Remainder
Missing the starting time Writing answer as "24 minutes" instead of "8:24 AM" Add the interval to the base clock time stated in the question

Practice Questions for Class 7 & 8

Solve these practice problems to test your mastery:

  1. Two bells toll at intervals of 8 and 12 minutes. If they toll together at 10:00 AM, at what time will they toll together next?
  2. Find the smallest number divisible by 6, 9, and 15.
  3. Three students step off together. Their steps measure 40 cm, 48 cm, and 60 cm. What is the minimum distance each should walk to cover the distance in complete steps?
  4. Find the smallest number which when divided by 15, 20, and 25 leaves a remainder of 7 in each case.
  5. Four bells toll at intervals of 6, 8, 12, and 18 minutes. If they toll together at 12:00 noon, when will they toll together next?
Answers: 1) 10:24 AM  |  2) 90  |  3) 240 cm (2.4 m)  |  4) 307  |  5) 1:12 PM (72 min later)

Frequently Asked Questions

Quick answers to common questions about Class 7/8 LCM word problems.

What are LCM word problems?

LCM word problems are real-life scenarios where you must find the minimum time, distance, or count where repeating events align or occur together.

How do I identify an LCM problem versus an HCF problem?

LCM problems involve repeating cycles meeting simultaneously ("together", "minimum time", "least distance"). HCF problems involve dividing quantities into equal groups ("maximum size", "greatest length", "largest container").

Why do bells ringing together require LCM?

Because each bell chimes at multiples of its period. All bells toll together at a common multiple. The very first time they do so is at the Least Common Multiple (LCM).

How do remainder word problems work with LCM?

When a number leaves a remainder r when divided by several numbers, find the LCM of those numbers and add r: Required number = LCM + r.

Class 7/8 Mathematical Glossary

Key definitions for school and Olympiad exams.

Least Common Multiple (LCM)
The smallest positive integer that is divisible by each of two or more given numbers without remainder.
Simultaneous Occurrence
Events happening at the exact same instant, determined by the LCM of their cycle periods.
Gear Mesh Alignment
The point where marked teeth on two gears re-engage, calculated using LCM of their teeth counts.
Co-prime Integers
Numbers sharing no common factors other than 1; their LCM is equal to their direct product.